void operator=(const Buffer& buf)
    {
        delete[] _data;
        _size = buf._size;
        _data = new char[_size];
        memcpy(_data, buf._data, _size);
    }
   

void operator=(const Buffer& buf)
{
    if (&buf == this)
        return;
    delete[] _data;
    _size = buf._size;
    _data = new char[_size];
    memcpy(_data, buf._data, _size);
} 

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Original post by Redleaf

void operator=(const Buffer& buf)
{
    if (&buf == this)
        return;
    delete[] _data;
    _size = buf._size;
    _data = new char[_size];
    memcpy(_data, buf._data, _size);
}    

"Don't be afraid to dream, for out of such fragile things come miracles."

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Buffer & operator=(const Buffer& buf)
{
    if (&buf != this)
    {
      delete[] _data;
      _size = buf._size;
      _data = new char[_size];
      memcpy(_data, buf._data, _size);
    }
    return *this;
}    

quote:

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std::string input
std::cin >> input;

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quote:

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This series is intended to give the reader the information necessary to create a scripting system of his/her own from the ground up.

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This example will be object-based, but not necessarily object-oriented; the classes can therefore easily be replaced by structures for those dealing with a pure C mentality.

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Original post by Redleaf
I suggest you read that part of the standard again:
[lib.global.names] 17.4.3.1.2 Global names

Certain sets of names and function signatures are always reserved to the implementation:

— Each name that contains a double underscore (__) or begins with an underscore followed by an uppercase letter (2.11) is reserved to the implementation for any use.

— Each name that begins with an underscore is reserved to the implementation for use as a name in the global namespace.

Member variables are certainly not part of the global namespace.

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quote:

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As to buffer being a reimplementation of vector, it's certainly not. It's quite a bit more simplistic.

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class Buffer
{
public:
    Buffer() { }
    Buffer(const char* d) : data(d) { }
    const char* Data() const { return data.c_str(); }
private:
    std::string data;
};
  

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That's not going to grab an entire line if there are spaces.

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std::string string;
std::getline(std::cin, string, '\n');
  

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I think I explained my choice as to files.

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