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 Bresenham's Line and Circle Algorithms
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Reply Quoting This MessageEdit Message yoho    Member since: 7/10/2003
 Posted - 7/10/2003 9:07:45 PM
Could someone explain the program line: d = (2 * deltay) - deltax
It's under Line Algorithm about in the middle.
Thanks
-Y
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Reply Quoting This MessageEdit Message zeiscra    Member since: 10/5/2003  From: USA
 Posted - 10/5/2003 1:37:00 AM
I'm trying to convert this code to c++, and I'm unfamiliar with the pascal operator "shl." What exactly does this do?

Thanks,

Craig
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Reply Quoting This MessageEdit Message Myopic Rhino  Staff  Member since: The dawn of time   From: Temecula, CA, United States
 Posted - 10/6/2003 3:35:01 AM
It's "SHift Left" (i.e. <<)
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Reply Quoting This MessageEdit Message Anonymous Poster  
Warning Level: 10%
 Posted - 6/4/2005 10:24:00 PM
http://www.cs.fit.edu/~wds/classes/graphics/Rasterize/bresenham.html
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Reply Quoting This MessageEdit Message Anonymous Poster  
Warning Level: 10%
 Posted - 11/13/2005 3:51:01 AM
Could anyone explain me these:
d := 3 - (2 * RADIUS)
d := d + (4 * x) + 6
d := d + 4 * (x - y) + 10
in the Bresenham's Circle Algorithm?
I dont underestand these constants!
Help! :(

Im not english speaking - sorry for bad EN
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Reply Quoting This MessageEdit Message Anonymous Poster  
Warning Level: 10%
 Posted - 11/13/2005 3:51:37 AM
Could anyone explain me these:
d := 3 - (2 * RADIUS)
d := d + (4 * x) + 6
d := d + 4 * (x - y) + 10
in the Bresenham's Circle Algorithm?
I dont underestand these constants!
Help! :(

Im not english speaking - sorry for bad EN
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Reply Quoting This MessageEdit Message Anonymous Poster  
Warning Level: 10%
 Posted - 11/16/2005 11:15:42 AM
I found it!
For my future friends!: http://www.netnam.vn/unescocourse/computervision/63.htm
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Reply Quoting This MessageEdit Message Oceano    Member since: 6/1/2009  From: Barcelona, Spain
 Posted - 6/12/2009 10:08:34 AM
In this web:

http://sites.google.com/site/proyectosroboticos/

you were solving the algorithm of bresenham for 2D, 3D, 4D ... up to(even) 6D.

Bresenham's algorithm does many things, besides lines.

And

you will solve the inverse kinematics from 2 up to 5 degrees of freedom.

Regards.
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