But ignoring that; yes, the logic is otherwise OK, as long as you index the array properly. You probably want this instead though:
if(exp>=exptilnextlevel[level])
{
++level;
}
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#ActualBrother Bob
Posted 17 February 2012 - 05:41 PM
No. You have an array with 99 element, and the index 99 refers to the 100th element. It is outside the array, so it's not a valid array element.
But ignoring that; yes, the logic is otherwise OK, as long as you index the array properly. You probably want this instead though:
But ignoring that; yes, the logic is otherwise OK, as long as you index the array properly. You probably want this instead though:
#2Brother Bob
Posted 17 February 2012 - 05:40 PM
No. You have an array with 99 element, and the index 99 refers to the 100th element. It is outside the array, so it's not a valid array element.
But ignoring that; yes, the logic is otherwise OK, as long as you index the array properly. You probably want this instead:
But ignoring that; yes, the logic is otherwise OK, as long as you index the array properly. You probably want this instead:
if(exp>=exptilnextlevel[level])
{
++level;
}
#1Brother Bob
Posted 17 February 2012 - 05:40 PM
No. If you have an array with 99 element, and the index 99 refers to the 100th element. It is outside the array, so it's not a valid array element.
But ignoring that; yes, the logic is otherwise OK, as long as you index the array properly. You probably want this instead:
But ignoring that; yes, the logic is otherwise OK, as long as you index the array properly. You probably want this instead:
if(exp>=exptilnextlevel[level])
{
++level;
}