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### #ActualTheUnbeliever

Posted 13 June 2012 - 05:38 PM

Does the function return two values?

It returns a pair or 2D vector; the authors have opted for [a;b] over (a,b) to improve legibility.

The other line I had trouble with was this one: min s' (is element of) pred(s) (g(s'), c(s', s)). I don't get that one at all. The s' in pred() with the smallest g or c?

I don't see this line. I do see min s' (is element of) pred(s) (g(s') + c(s', s)) - i.e. the minimum of the expression on the right over all predecessors of s.

EDIT: slightly clearer wording.

### #2TheUnbeliever

Posted 13 June 2012 - 05:38 PM

Does the function return two values?

It returns a pair or 2D vector; the authors have opted for [a;b] over (a,b) to improve legibility.

The other line I had trouble with was this one: min s' (is element of) pred(s) (g(s'), c(s', s)). I don't get that one at all. The s' in pred() with the smallest g or c?

I don't see this line. I do see min s' (is element of) pred(s) (g(s') + c(s', s)) - i.e. the minimum of the expression on the right over all predecessors of s.

### #1TheUnbeliever

Posted 13 June 2012 - 05:37 PM

Does the function return two values?

It returns a pair or 2D vector; the authors have opted for [a;b] over (a,b) to improve legibility.

The other line I had trouble with was this one: min s' (is element of) pred(s) (g(s'), c(s', s)). I don't get that one at all. The s' in pred() with the smallest g or c?

I don't see this line. I do see min s' (is element of) pred(s) (g(s') + c(s', s)) - i.e. minimize the expression on the right over all predecessors of s.

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