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#ActualXanather

Posted 19 June 2012 - 05:55 AM

Wow, thank you for that, I never knew that Posted Image.

So your saying with UTF-8 encoding, when you use the English language (well ASCII characters) the last bit is constantly in the binary state of 1, as this is a full character itself? This really makes sense if this is true. And other non-ASCII characters may have several 7-bit data bytes with the last bit (8th bit) having a binary state of 0 (unless of course, its the last byte of the character indicating that you have all the data in order to decode)?

What I dont understand though is how you could pack 6-bits of numeric info into the last byte?

(I didnt type that too well... heh)

#2Xanather

Posted 19 June 2012 - 05:46 AM

Wow, thank you for that, I never knew that Posted Image. I may just implement that, really smart and efficient! : D

So your saying with UTF-8 encoding, when you use the English language (well ASCII characters) the last bit is constantly in the binary state of 1, as this is a full character itself? This really makes sense if this is true. And other non-ASCII characters may have several 7-bit data bytes with the last bit (8th bit) having a binary state of 0 (unless of course, its the last byte of the character indicating that you have all the data in order to decode)?

(I didnt type that too well... heh)

#1Xanather

Posted 19 June 2012 - 05:35 AM

Wow, thank you for that, I never knew that :). I may just implement that, really smart! :D

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