I don't get it. Unless tempValues is empty or contains only one element, you can just as well call myVector.clear() and be done with it. As soon as this for-loop has executed the second time, your vector will always be empty.
At this point it's not a matter of syntax, it's a matter of the whole approach being simply wrong. The only place where a loop should iterate over all tempValues is inside your predicate (and even there I'd prefer find).
That's right, exactly what's happening.
The solution I used is the one suggested by krippy2k8, which uses std::find into the predicate:
struct myPred
{
myPred(const std::vector<int>& toCheck )
:someValuesToCheck(toCheck)
{}
bool operator()(int val)
{
return (std::find( someValuesToCheck.begin(), someValuesToCheck.end(), val ) == someValuesToCheck.end() );
}
const std::vector<int>& someValuesToCheck;
};
someValues.erase( std::remove_if( someValues.begin(), someValues.end(), myPred(someValuesToCheck) ), someValues.end() );
Nonetheless, it was very interesting to read rip-off, Brother Bob and all other folks suggestions. I'm very new to vectors and very confused about those. Hopefully I learned something new today.