Not sure if the logic is correct.
y = 0;
t = 0;
while(x)
{
y |= ((x&1) << t);
t++;
x >>= 2;
}
Show differencesHistory of post edits
#Actualpapalazaru
Posted 16 October 2012 - 01:13 PM
something like this?
Not sure if the logic is correct.
Not sure if the logic is correct.
#4papalazaru
Posted 16 October 2012 - 01:12 PM
something like this?
Not sure if the logic is correct.
Not sure if the logic is correct.
y = 0;
t = 0;
while(x)
{
y |= ((x&1) << t);
t++;
x >> 2;
}
#3papalazaru
Posted 16 October 2012 - 01:12 PM
something like this?
Not sure if the logic is correct.
Not sure if the logic is correct.
y = 0;
while(x)
{
y |= ((x&1) << t);
t++;
x >> 2;
}
#2papalazaru
Posted 16 October 2012 - 01:11 PM
something like this?
Not sure if the logic is correct.
[source lang="cpp"]y = 0;while(x){ y |= ((x&1) << t); t++; x >> 2;}[/source]
Not sure if the logic is correct.
[source lang="cpp"]y = 0;while(x){ y |= ((x&1) << t); t++; x >> 2;}[/source]
#1papalazaru
Posted 16 October 2012 - 01:11 PM
something like this?
Not sure if the logic is correct.
[source lang="cpp"]y = 0;while(x){ y |= ((x&1) << t); t++; x >> 2;}[/source]
Not sure if the logic is correct.
[source lang="cpp"]y = 0;while(x){ y |= ((x&1) << t); t++; x >> 2;}[/source]