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#ActualÁlvaro

Posted 17 November 2012 - 02:06 PM

I did some back-of-the-envelope computation and came up with pi*sqrt(radius/2) . Try it, or something proportional to it and see how well it works perceptually.

#1Álvaro

Posted 17 November 2012 - 02:06 PM

I did some back-of-the-envelope computation and came up with pi/sqrt(2/radius) . Try it, or something proportional to it and see how well it works perceptually.

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