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#Actualmax343

Posted 29 November 2012 - 10:44 AM

Yes So it doesn't prove my formula with vertices ??
The aim of this formula is to not use distance but just vertices to gain time !


Why not?
For tetrahedron: A*d/3 == Det(v1-v0,v2-v0,v3-v0)/6, where 'A' is the area of some triangle and 'd' is the distance from the opposing vertex to the plane of the triangle. In the Det formula v1,v2,v3 define the same triangle, while v0 is the opposing vertex.

#1max343

Posted 29 November 2012 - 10:42 AM

Yes So it doesn't prove my formula with vertices ??
The aim of this formula is to not use distance but just vertices to gain time !


Why not?
For tetrahedron: A*h/3 == Det(v1-v0,v2-v0,v3-v0)/6, where 'A' is the area of some triangle and 'h' is the distance from the opposing vertex to the plane of the triangle. In the Det formula v1,v2,v3 define the same triangle, while v0 is the opposing vertex.

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