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#ActualTiagoCosta

Posted 19 January 2013 - 06:59 AM

Basically:

 

log2(largetsMipSize)+1

 

log2(256) + 1 = 8 + 1 = 9


#4TiagoCosta

Posted 19 January 2013 - 06:59 AM

<p>Basically:</p>
<p>&nbsp;</p>
<p>log<sub>2</sub>(largetsMipSize)+1</p>
<p>&nbsp;</p>
<p>log<sub>2</sub>(256) + 1 = 8 + 1 = 9</p>

#3TiagoCosta

Posted 19 January 2013 - 06:59 AM

Basically:

 

log2(largetsMipSize)+1


#2TiagoCosta

Posted 19 January 2013 - 06:57 AM

Basically:

<img src="http://www.codecogs.com/eq.latex?log_2(largestMipSize)" />

#1TiagoCosta

Posted 19 January 2013 - 06:55 AM

Basically:<br /><img data-cke-saved-src="http://latex.codecogs.com/eq.latex?log_2(largestMipSize)+1" src="http://latex.codecogs.com/eq.latex?log_2(largestMipSize)+1" /><br />&nbsp;<br /><img data-cke-saved-src="http://latex.codecogs.com/eq.latex?log_2(256)+1%20=%208+1%20=%209" src="http://latex.codecogs.com/eq.latex?log_2(256)+1%20=%208+1%20=%209" />

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