Jump to content

  • Log In with Google      Sign In   
  • Create Account


#ActualRavyne

Posted 29 January 2013 - 04:16 PM

h' = h * length(S*(b - a)) / (length(b - a))


Um... Aren't you just multiplying by S then?

Think about what that says in plain english: The new 'h' is the old 'h' times the scaled length of a line, divided by the length of the same line.

#1Ravyne

Posted 29 January 2013 - 04:15 PM

h' = h * length(S*(b - a)) / (length(b - a)) 

 

Um... Aren't you just multiplying by S then?

 

Think about what that says in plain english: The new 'h' is the old 'h' times the length of a scaled line, divided by the length of the line.


PARTNERS