h' = h * length(S*(b - a)) / (length(b - a))
Um... Aren't you just multiplying by S then?
Think about what that says in plain english: The new 'h' is the old 'h' times the scaled length of a line, divided by the length of the same line.
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#ActualRavyne
Posted 29 January 2013 - 04:16 PM
Um... Aren't you just multiplying by S then?
Think about what that says in plain english: The new 'h' is the old 'h' times the scaled length of a line, divided by the length of the same line.
#1Ravyne
Posted 29 January 2013 - 04:15 PM
h' = h * length(S*(b - a)) / (length(b - a))
Um... Aren't you just multiplying by S then?
Think about what that says in plain english: The new 'h' is the old 'h' times the length of a scaled line, divided by the length of the line.