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### #ActualCaptacha

Posted 12 February 2013 - 07:27 PM

Yes, it does. openList is passed as vector<Node>& openList. Here's the general algorithm for it. The functions in the if statement's body don't affect either list.

Node* tmp;
if(!hasWall(parentNode.pos.x, parentNode.pos.y-1, wallCords) && !onClosedList(Position(parentNode.pos.x, parentNode.pos.y-1), closedList))
{
tmp = new Node(Position(parentNode.pos.x, parentNode.pos.y-1), &parentNode);
openList.push_back(*tmp);
}

### #4Captacha

Posted 12 February 2013 - 07:27 PM

Yes, it does. openList is passed as vector<Node>& openList. Here's the general algorithim for it. The functions in the if statement's body don't affect either list.

Node* tmp;
if(!hasWall(parentNode.pos.x, parentNode.pos.y-1, wallCords) && !onClosedList(Position(parentNode.pos.x, parentNode.pos.y-1), closedList))
{
tmp = new Node(Position(parentNode.pos.x, parentNode.pos.y-1), &parentNode);
openList.push_back(*tmp);
}

### #3Captacha

Posted 12 February 2013 - 07:26 PM

Yes, it does. openList is passed as vector<Node>& openList. Here's a sample. The functions in the if statement's body don't affect either list.

Node* tmp;
if(!hasWall(parentNode.pos.x, parentNode.pos.y-1, wallCords) && !onClosedList(Position(parentNode.pos.x, parentNode.pos.y-1), closedList))
{
tmp = new Node(Position(parentNode.pos.x, parentNode.pos.y-1), &parentNode);
openList.push_back(*tmp);
}

### #2Captacha

Posted 12 February 2013 - 07:25 PM

Yes, it does. openList is passed as vector<Node>& openList. Here's a sample. The functions in the if statement's body don't affect either list.

Node*
tmp;if(!hasWall(parentNode.pos.x,
parentNode.pos.y-1, wallCords) && !onClosedList(Position(parentNode.pos.x,
parentNode.pos.y-1), closedList)){tmp = new Node(Position(parentNode.pos.x,
parentNode.pos.y-1), &parentNode);openList.push_back(*tmp);}

### #1Captacha

Posted 12 February 2013 - 07:25 PM

Yes, it does. openList is passed as vector<Node>& openList. Here's a sample. The functions in the if statement's body don't affect either list.

Node*
tmp;if(!hasWall(parentNode.pos.x,
parentNode.pos.y-1, wallCords) && !onClosedList(Position(parentNode.pos.x,
parentNode.pos.y-1), closedList)){tmp = new Node(Position(parentNode.pos.x,
parentNode.pos.y-1), &parentNode);openList.push_back(*tmp);}

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