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#Actualapatriarca

Posted 15 May 2013 - 06:58 AM

You start from the parametric Bézier curve formula and rewrite the terms until you obtain the desired formula. This is simple algebra, nothing complicated. For example, for the quadratic case:

 

acv2qqk.png

 

The derivation in the cubic case is similar. But I have always found the Bézier formula a much more useful formulation. Why do you want the coefficients of the polynomial?

 

EDIT: corrected the formula..


#2apatriarca

Posted 15 May 2013 - 06:53 AM

You start from the parametric Bézier curve formula and rewrite the terms until you obtain the desired formula. This is simple algebra, nothing complicated. For example, for the quadratic case:

 

b2p2m7q.png

 

The derivation in the cubic case is similar. But I have always found the Bézier formula a much more useful formulation. Why do you want the coefficients of the polynomial?


#1apatriarca

Posted 15 May 2013 - 06:50 AM

You start from the parametric Bézier curve formula and rewrite the terms until you obtain the desired formula. This is simple algebra, nothing complicated. For example, for the quadratic case:

 

b2p2m7q.png


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