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#Actualpatishi

Posted 01 July 2013 - 08:42 PM

ok thanks!  sorry for the confusion..I should have known that me not using the 49 bits method will not work in this case.  so i think i will go for the zobrist solution,seems simple enough.                  Although i can't help thinking that if a combination of 2 bitboards (white and black both)  is unique for each position (e.g there can't be a situation with the same white bitboard and the same black bitboard together) , there is a straight forward way to produce some kind of key  (something like addition of the two bitboards together + another something smile.png  )      but i afraid that if i will go for something of my own i will get identical keys / codes for different positions.     so  i will go for the safe and popular method of zobrist.      


#3patishi

Posted 01 July 2013 - 08:41 PM

ok thanks!  sorry for the confusion..I should have known that me not using the 49 bits method will not work in this case.  so i think i will go for the zobrist solution,seems simple enough.                  Although i can't help thinking that if a combination of 2 bitboards (white and black both)  is unique for each position, there is a straight forward way to produce some kind of key  (something like addition of the two bitboards together + another something smile.png  )      but i afraid that if i will go for something of my own i will get identical keys / codes for different positions.     so  i will go for the safe and popular method of zobrist.      


#2patishi

Posted 01 July 2013 - 08:41 PM

ok thanks!  sorry for the confusion..I should have known that me not using the 49 bits method will not work in this case.  so i think i will go for the zobrist solution,seems simple enough.                  Although i can't help thinking that if a combination of 2 bitboards (white and black both)  is unique for each position, there is a straight forward way to produce some kind of key  (something like addition of the two bitboards together + another something smile.png  )      but i afraid that if i will go for something of my own i will get identical keys / codes for some positions.     so  i will go for the safe and popular method of zobrist.      


#1patishi

Posted 01 July 2013 - 08:40 PM

ok thanks!  sorry for the confusion..I should have known that me not using the 49 bits method will not work in this case.  so i think i will go for the zobrist solution,seems simple enough.                  Although i can't help thinking that if a combination of 2 bitboards (white and black both)  is unique for each position, there is a straight forward way to produce some kind of key  (something like addition of the two bitboards together + another something :)  )      but i afraid that if i will go for something of my own i will get identical results for some positions.     so  i will go for the safe and popular method of zobrist.      


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