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### #ActualBurnt_Fyr

Posted 04 September 2013 - 01:39 PM

Are you looking for a quadratic that goes through those 3 points, or are controlled by those 3 points?

If controlled, a point p on a curve c can be found using t, where 0 < t < 1 from start to finish.

v0 = (1-t)*x + t *y

v1 = (1-t)*y + t * z

and finally:

p = (1-t)*v0 + t*v1

if you are looking for a curve that fits those 3 points, i'm not 100% sure, but I think that more than 1 curve could fit.

EDIT: I stand corrected. Essentially you create the quadratic for each point and then with those 3 equations, Solve for a,b, and c.

EDIT2: I think i feel vindicated, multivariable quadratics would allow for an infinite number of quadratics that fit those points

### #3Burnt_Fyr

Posted 04 September 2013 - 01:37 PM

Are you looking for a quadratic that goes through those 3 points, or are controlled by those 3 points?

If controlled, a point p on a curve c can be found using t, where 0 < t < 1 from start to finish.

v0 = (1-t)*x + t *y

v1 = (1-t)*y + t * z

and finally:

p = (1-t)*v0 + t*v1

if you are looking for a curve that fits those 3 points, i'm not 100% sure, but I think that more than 1 curve could fit.

EDIT: I stand corrected. Essentially you create the quadratic for each point and then with those 3 equations, Solve for a,b, and c.

### #2Burnt_Fyr

Posted 04 September 2013 - 01:35 PM

Are you looking for a quadratic that goes through those 3 points, or are controlled by those 3 points?

If controlled, a point p on a curve c can be found using t, where 0 < t < 1 from start to finish.

v0 = (1-t)*x + t *y

v1 = (1-t)*y + t * z

and finally:

p = (1-t)*v0 + t*v1

if you are looking for a curve that fits those 3 points, i'm not 100% sure, but I think that more than 1 curve could fit.

EDIT: I stand corrected. Essentially you create the quadratic for each point and then with those 3 equations, Solve for a,b, and c.

### #1Burnt_Fyr

Posted 04 September 2013 - 01:29 PM

Are you looking for a quadratic that goes through those 3 points, or are controlled by those 3 points?

If controlled, a point p on a curve c can be found using t, where 0 < t < 1 from start to finish.

v0 = (1-t)*x + t *y

v1 = (1-t)*y + t * z

and finally:

p = (1-t)*v0 + t*v1

if you are looking for a curve that fits those 3 points, i'm not 100% sure, but I think that more than 1 curve could fit.

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