public:
char stuff;
private:
int stuff2;
};
llave *ptr;
void main() {
ptr = new llave[number_here];
ptr[x].stuff = 'C';
}
------------------
E-mail with questions, comments, and retorts.
Dynamic class pointer arrays?
class llave {
public:
char stuff;
public:
char stuff;
Author
Thanks for the answer but unfortunatley 
i already know how to do that. What i need to know is how to create an dynamic pointer array that can grow and shrink in size in runtime.
i already know how to do that. What i need to know is how to create an dynamic pointer array that can grow and shrink in size in runtime.
Whitehouse:
How about using a linked list with whatever data members you need. To use it like an array, overload the [] operator.
Six
Try searching for it on yahoo or another search engine. It is a basic concept, so you should be able to find plenty of information.
Author
Simple question, hard answer... I just need help with how to initialize and use them in my game.
------------------
----------------------
Kim Forsberg
WorldScape Productions
----------------------
// linklist.cpp
// linked list
#include
// linked list
#include
struct link // one element of list
{
int data; // data item
link* next; // pointer to next link
};
class linklist // a list of links
{
private:
link* first; // pointer to first link
public:
linklist() // no-argument constructor
{ first = NULL; } // no first link
void additem(int d); // add data item (one link)
void display(); // display all links
};
void linklist::additem(int d) // add data item
{
link* newlink = new link; // make a new link
newlink->data = d; // give it data
newlink->next = first; // it points to next link
first = newlink; // now first points to this
}
void linklist::display() // display all links
{
link* current = first; // set ptr to first link
while( current != NULL ) // quit on last link
{
cout << endl << current->data; // print data
current = current->next; // move to next link
}
}
void main()
{
linklist li; // make linked list
li.additem(25); // add four items to list
li.additem(36);
li.additem(49);
li.additem(64);
li.display(); // display entire list
}
i got this out of a book dont know if itll help you any
This topic is closed to new replies.
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