rotate point around origin by angle
I am not 100% clear on the math for what i am trying to do... let me give you a sample situation... i have a point lets say 15,5 which is the point of an arrow. I have another point which is the base of the arrow (my origin) which is 2,2... what i am doing is i need to rotate the arrow on its origin by 45 degrees and find out the new point for the tip... if somone could give me the equation and a sample solution using the equation for these values it would be great!
This isn't homework, is it? (Just checking...)
Anyway, to rotate about an arbitrary point:
1. Translate the point by the negative of the pivot point
2. Rotate the point using the standard equation for 2-d (or 3-d) rotation
3. Translate back
Anyway, to rotate about an arbitrary point:
1. Translate the point by the negative of the pivot point
2. Rotate the point using the standard equation for 2-d (or 3-d) rotation
3. Translate back
jyk is correct, and here is an example of how you would do that:
Firstly, translate:
v = (15,5) - (2,2) = (13,3)
Now rotate by 45°:
v = (13*cos 45° - 3*sin 45°, 13*sin 45° + 3*cos 45°) = (7.07.., 11.31..)
And finally, translate back:
v = v + (2,2) = (9.07.., 13.31..)
And there's your answer.
(For the rotation stage, you might find this useful:
http://mathworld.wolfram.com/RotationMatrix.html )
Firstly, translate:
v = (15,5) - (2,2) = (13,3)
Now rotate by 45°:
v = (13*cos 45° - 3*sin 45°, 13*sin 45° + 3*cos 45°) = (7.07.., 11.31..)
And finally, translate back:
v = v + (2,2) = (9.07.., 13.31..)
And there's your answer.
(For the rotation stage, you might find this useful:
http://mathworld.wolfram.com/RotationMatrix.html )
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