2 replies to this topic

[James Leighe]

how do you implement a function that returns a function pointer without using typedefs that's also in a class? (in c++)

i'm pretty sure i can declare it like this

class Stupid
{
public:
  void (*GetFnValue( char* key ))( );
};

but i'm lost at implementation, something like

void (*fn)( )
Stupid::GetFnValue( char* key )
{
  return whatev;
}

tanks

[SiCrane]

You could do:

void (*Stupid::GetFnValue( char* key ))()
{
  return 0;
}

but you should probably just typedef the function pointer.

[Misery]

If it is C++ maybe it is worth trying to use functor instead of function pointers.

class Stupid
{
public:
  void (*GetFnValue( char* key ))( );
};

The above code could be changed to:

class Stupid
{
public:
  MyFunctorClass FunRetFun(argtypes arguments)
};

and the latter part:

class MyFunctor{
   public:
   MyFunctor(char* key)
   {
	 //do some stuff
   }
}

and if You want a function returning a function it would just be sth like this:

MyFunctorClass Stupid::FunRetFun(argtypes arguments)
{
  //do something
return SomeInstance of MyFunctorClass;
}

I don't know if thats handy in Your application, but in a few programs that I have created it worked very well and it was much more comfy to use.
Regards