5 replies to this topic

[Shippou]

I would like to knoow if my math is correct in calculating the distance between 2 objects on a 2D plain:

def distance(x1,x2,y1,y2):
	# A squared + B squared = C squared
	return ( ( (x2 - x1)**2) + ( (y2-y1)**2) )**.5
# Object 1 Location
coordinate1 = 2,8	 # x,y
# Object 2 Location
coordinate2 = 5,10	 # x,y
print (distance(coordinate1[0],coordinate2[0],coordinate1[1],coordinate2[1]))

Thanks.

[jjd]

I would like to knoow if my math is correct in calculating the distance between 2 objects on a 2D plain:

def distance(x1,x2,y1,y2):
	# A squared + B squared = C squared
	return ( ( (x2 - x1)**2) + ( (y2-y1)**2) )**.5
# Object 1 Location
coordinate1 = 2,8	 # x,y
# Object 2 Location
coordinate2 = 5,10	 # x,y
print (distance(coordinate1[0],coordinate2[0],coordinate1[1],coordinate2[1]))

Thanks.

Yes, that is correct.

-Josh

[HappyCoder]

yup. That distance equation will give you the distance between two points.

[Cornstalks]

Yes, your math is correct.

[edit]

Holy crap! Ninja'd twice!

[Shippou]

Thank you.

[Narf the Mouse]

As a side note, it's also useful to include a "DistanceSquared" function, which omits the square root - If you're simply comparing which is farther, and don't need to know how far, omitting a costly square root can save significant time in time-sensitive applications.