Jump to content

  • Log In with Google      Sign In   
  • Create Account

Banner advertising on our site currently available from just $5!


1. Learn about the promo. 2. Sign up for GDNet+. 3. Set up your advert!


Math Check: Distance Between 2 Obbjects


Old topic!
Guest, the last post of this topic is over 60 days old and at this point you may not reply in this topic. If you wish to continue this conversation start a new topic.

  • You cannot reply to this topic
5 replies to this topic

#1 Code Fox   GDNet+   -  Reputation: 2539

Like
0Likes
Like

Posted 14 January 2012 - 01:01 PM

I would like to knoow if my math is correct in calculating the distance between 2 objects on a 2D plain:
def distance(x1,x2,y1,y2):
	# A squared + B squared = C squared
	return ( ( (x2 - x1)**2) + ( (y2-y1)**2) )**.5
# Object 1 Location
coordinate1 = 2,8	 # x,y
# Object 2 Location
coordinate2 = 5,10	 # x,y
print (distance(coordinate1[0],coordinate2[0],coordinate1[1],coordinate2[1]))


Thanks.

The most effective debugging tool is still careful thought, coupled with judiciously placed print statements. ~ Brian W. Kernighan

 

Code_Fox_Sig.png


Sponsor:

#2 jjd   Crossbones+   -  Reputation: 2126

Like
0Likes
Like

Posted 14 January 2012 - 01:15 PM

I would like to knoow if my math is correct in calculating the distance between 2 objects on a 2D plain:

def distance(x1,x2,y1,y2):
	# A squared + B squared = C squared
	return ( ( (x2 - x1)**2) + ( (y2-y1)**2) )**.5
# Object 1 Location
coordinate1 = 2,8	 # x,y
# Object 2 Location
coordinate2 = 5,10	 # x,y
print (distance(coordinate1[0],coordinate2[0],coordinate1[1],coordinate2[1]))


Thanks.


Yes, that is correct.

-Josh

--www.physicaluncertainty.com
--linkedin
--irc.freenode.net#gdnet


#3 HappyCoder   Members   -  Reputation: 3077

Like
0Likes
Like

Posted 14 January 2012 - 01:16 PM

yup. That distance equation will give you the distance between two points.

#4 Cornstalks   Crossbones+   -  Reputation: 6999

Like
0Likes
Like

Posted 14 January 2012 - 01:16 PM

Yes, your math is correct.

[edit]

Holy crap! Ninja'd twice!
[ I was ninja'd 71 times before I stopped counting a long time ago ] [ f.k.a. MikeTacular ] [ My Blog ] [ SWFer: Gaplessly looped MP3s in your Flash games ]

#5 Code Fox   GDNet+   -  Reputation: 2539

Like
0Likes
Like

Posted 14 January 2012 - 01:42 PM

Thank you.

The most effective debugging tool is still careful thought, coupled with judiciously placed print statements. ~ Brian W. Kernighan

 

Code_Fox_Sig.png


#6 Narf the Mouse   Members   -  Reputation: 318

Like
1Likes
Like

Posted 16 January 2012 - 03:37 PM

As a side note, it's also useful to include a "DistanceSquared" function, which omits the square root - If you're simply comparing which is farther, and don't need to know how far, omitting a costly square root can save significant time in time-sensitive applications.




Old topic!
Guest, the last post of this topic is over 60 days old and at this point you may not reply in this topic. If you wish to continue this conversation start a new topic.



PARTNERS