for (i = 0; i < foo; ++i)
{
for (j = 0; j < bar; ++i)
{
}
}
Luckly I have done this enough that I have gotten pretty good at finding it.
Posted 26 February 2012 - 12:40 AM
for (unsigned len = 0; *name; len++, *name++) {
Posted 26 February 2012 - 05:59 AM
MaulingMonkey, on 26 February 2012 - 04:28 AM, said:
Posted 28 February 2012 - 11:20 AM
entity.Location = "http://....somebiglongstring.html"
Posted 28 February 2012 - 12:23 PM
JavierMC, on 28 February 2012 - 04:09 AM, said:
uint16 numVerts = 0; for(size_t i = 0; i<70000; i++) numVerts++;
MaulingMonkey, on 28 February 2012 - 10:43 AM, said:
for ( size_t i = 0 ; i < v.size() - 1 ; ++i )
{
...
}Posted 28 February 2012 - 12:28 PM
Alpha_ProgDes, on 28 February 2012 - 12:23 PM, said:
Posted 28 February 2012 - 12:38 PM
swiftcoder, on 28 February 2012 - 12:28 PM, said:
Posted 28 February 2012 - 12:47 PM
way2lazy2care, on 28 February 2012 - 12:38 PM, said:
Posted 28 February 2012 - 01:18 PM
i < size()-1. The last element won't get counted for. And of course, if size() returns 0, it will evaluate to a very large number.
Posted 28 February 2012 - 02:21 PM
for x in a:
for y in a:
# Do something with x[0] ... y[1]
#A short time later...
for x in a:
#Do something else x[0] .... y[1]