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cant render a rectange in rhw space


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#1   Members   

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Posted 29 February 2012 - 09:24 AM

struct CUSTOMVERTEX {FLOAT X, Y, Z, RHW; DWORD COLOR;};
#define CUSTOMFVF (D3DFVF_XYZRHW | D3DFVF_DIFFUSE )


I an trying to render a rectangle like this, it renders in linelist mode so i can see if the cordinates are correct, so what i want todo now is change it to 2 tranges to make a solid rectangle, but i can only seem to make 1 trangle render , not sure why?

CUSTOMVERTEX vertices[] =
	{
		//x	   //y
/*450 */{ 150.0f, 62.5f, 0.5f, 1.0f, D3DCOLOR_XRGB(0, 0, 255), }, //top left
		{ 325.0f, 500.0f, 0.5f, 1.0f, D3DCOLOR_XRGB(0, 255, 0), }, //bottom right
		{ 150.0f, 500.0f, 0.5f, 1.0f, D3DCOLOR_XRGB(255, 0, 0), }, //bottom left

		{150.0f, 62.5f, 0.5f, 1.0f, D3DCOLOR_XRGB(0, 0, 255), }, //top left
		{ 325.0f, 62.5f, 0.5f, 1.0f, D3DCOLOR_XRGB(0, 0, 255), }, //top right
		{ 325.0f, 500.0f, 0.5f, 1.0f, D3DCOLOR_XRGB(0, 0, 255), }, //bottom right
	};

	// create a vertex buffer interface called v_buffer
	d3ddev->CreateVertexBuffer(6*sizeof(CUSTOMVERTEX),
							   0,
							   CUSTOMFVF,
							   D3DPOOL_MANAGED,
							   &v_buffer,
							   NULL);

	VOID* pVoid;	// a void pointer

	// lock v_buffer and load the vertices into it
	v_buffer->Lock(0, 0, (void**)&pVoid, 0);
	memcpy(pVoid, vertices, sizeof(vertices));
	v_buffer->Unlock();

in the rendering function

// select which vertex format we are using
		d3ddev->SetFVF(CUSTOMFVF);

		// select the vertex buffer to display
		d3ddev->SetStreamSource(0, v_buffer, 0, sizeof(CUSTOMVERTEX));

		// copy the vertex buffer to the back buffer
	   // d3ddev->DrawPrimitive(D3DPT_TRIANGLESTRIP, 0,2);

		d3ddev->DrawPrimitive(D3DPT_LINESTRIP, 0,5);

Attached Thumbnails

  • rectange-render-lines.jpg
  • rectange-render-triangles.jpg

:)

#2   Members   

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Posted 29 February 2012 - 09:44 AM

You want to render a triangle list, not a triangle strip. Change D3DPT_TRIANGLESTRIP to D3DPT_TRIANGLELIST

#3   Members   

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Posted 29 February 2012 - 10:00 AM

Maybe a problem is the order of vertices.
Please, swap vertices in your invlisble triangle.
(a, b, c) => (a, c, b)

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Posted 29 February 2012 - 10:12 AM

@OP: Turch is correct, I looked earlier and didn't spot it.

@kubera: that was my first instinct to, but both triangles are clearly wound the same based on vertex position

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Posted 29 February 2012 - 10:50 AM

You want to render a triangle list, not a triangle strip. Change D3DPT_TRIANGLESTRIP to D3DPT_TRIANGLELIST


that was it , thanks
:)

#6   Members   

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Posted 29 February 2012 - 10:50 AM

Would it be possible to set a texture now for this rectange?
:)

#7   Members   

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Posted 29 February 2012 - 11:36 AM

Yes, if you add a set of UV coordinates to your vertex struct and FVF:
struct CUSTOMVERTEX {FLOAT X, Y, Z, RHW; FLOAT U, V; DWORD COLOR;};
#define CUSTOMFVF (D3DFVF_XYZRHW | D3DFVF_TEX1 | D3DFVF_DIFFUSE )

I'm not sure if UV should come after the diffuse component - it's been years since I used FVF codes (And this is one of the many reasons not to use them)...

Steve Macpherson
Senior Systems Programmer

Rockstar North


#8   Members   

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Posted 29 February 2012 - 11:51 AM

but what about the texture cordinates? , ive got a feeling i need to lock the vertexbuffers and add the 1.0 and 0.0 offsets but ive only seen this done for a 3d cube in worldspace , not screenspace
:)

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Posted 29 February 2012 - 12:34 PM

uv coordinates are their own space, it doesn't matter if you're drawing in screen or world space, the uv's don't get affected by any of the transformations.

#10   Members   

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Posted 29 February 2012 - 12:44 PM

ok you have to remove the D3DFVF_DIFFUSE then it works :)
:)

#11   Members   

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Posted 29 February 2012 - 12:55 PM

This guide should help you.

#12   Members   

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Posted 29 February 2012 - 01:05 PM

Thanks for that guide, that is exactly what i was looking for
:)




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