Physics Question - How does thrust and mph work?
Members - Reputation: 1756
Posted 01 April 2012 - 02:18 PM
According to HowStuffWorks.com, 1 pound of thrust equals 32 feet per second, which works out at 21 mph. I'm assuming this means that 2 pounds of thrust on a 1 pound object would mean it would be:
(2 pounds of thrust - 1 pound of the object ) = 1 pound of thrust * 21mph = 21 mph.
If it was 3 pounds of thrust, it would be:
(3 pounds of thrust - 1 pound of the object ) = 2 pounds of thrust * 21 = 42 mph.
This seemed to make sense as a general rule, so I tried applying it to an F-15 which apparently generates around between 25,000 and 29,000 pounds of thrust per engine and the plane itself weighs around 45,000 pounds. So I take around (55,000 - 45,000) = 10,000 pounds of thrust * 21mph = 210000 mph!
Since we know the plane travels at 600mph and we know the weight is 45,000 pounds, does it not make sense that at 45,001 pounds of thrust the plane is moving forwards at 21mph? The original formula seems to suggest so. Would it not only then need 45,028 pounds of thrust to move at 600mph?
Where has my logic broken down? Is the formula I'm using broken? If I know the weight and pounds of thrust, is it not as straight forward to convert it to mph as I think it is? Perhaps there is just something special about twin jet engines that makes it a bad example to use?
disclaimer - I'm bad at maths and possibly as smart as a shoe
Members - Reputation: 773
Posted 01 April 2012 - 02:35 PM
and relate those to thrust: http://en.wikipedia.org/wiki/Thrust
Tie all those together into the equations of motion, and you can move stuff http://en.wikipedia....tions_of_motion
With all that said, i think your issue is you're multiplying a velocity by a force, which isnt giving you what you want. In your case you have a Thrust (which is a force), and a force is a mass (airplane) by an acceleration. if you know the mass of the airplane, and its current thrust, you can find an acceleration, you can then use that acceleration to figure out how fast the aircraft is going after a certain amount of time has passed.
Moderators - Reputation: 9125
Posted 01 April 2012 - 02:50 PM
The page also describes thrust fairly well: A pound of thrust is the amount of thrust it would take to keep a 1-pound object stationary against the force of gravity on Earth.
Crossbones+ - Reputation: 1997
Posted 01 April 2012 - 03:58 PM
If your signature on a web forum takes up more space than your average post, then you are doing things wrong.
Members - Reputation: 1756
Posted 01 April 2012 - 07:22 PM
If this is the page you've been reading, you have the units wrong. It doesn't say a pound of thrust is 32 feet per second, but 32 feet per second per second. It is an acceleration and not a speed, which makes sense since it is a force acting on a mass and thus accelerating it. The page also describes thrust fairly well: A pound of thrust is the amount of thrust it would take to keep a 1-pound object stationary against the force of gravity on Earth.
Ahhh, that might be the cause of the issue. I actually thought it was a typo at first
I just noticed Net Gnome updated his post which explains this really well. I think I'm getting confused with the acceleration and the final speed something is travelling at. I'm guessing then something could have a million pounds of thrust behind it, but without actually knowing when your taking the measurement you might as well be saying "This tree is as tall as a long piece of string"
Senior Staff - Reputation: 21497
Posted 24 March 2013 - 06:13 AM
I'm just going to punt this over to our Math & Physics forum.
- Jason Astle-Adams.
Crossbones+ - Reputation: 9961
Posted 24 March 2013 - 07:07 AM
necrooooo- ah, never mind.
The slowsort algorithm is a perfect illustration of the multiply and surrender paradigm, which is perhaps the single most important paradigm in the development of reluctant algorithms. The basic multiply and surrender strategy consists in replacing the problem at hand by two or more subproblems, each slightly simpler than the original, and continue multiplying subproblems and subsubproblems recursively in this fashion as long as possible. At some point the subproblems will all become so simple that their solution can no longer be postponed, and we will have to surrender. Experience shows that, in most cases, by the time this point is reached the total work will be substantially higher than what could have been wasted by a more direct approach.
- Pessimal Algorithms and Simplexity Analysis