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Debugging HLSL Shader


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#1 BMacZero   Members   -  Reputation: 116

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Posted 17 April 2012 - 03:55 PM

I'm having a lot of trouble debugging this specular shader in HLSL, I was hoping some extra eyes might be able to find the problem. Can anyone help me out here? I'm just banging my head against the wall at this point.

This is the shader code:

sampler TextureSampler : register(s0);

Texture2D<float4> xSpecularMap;
Texture2D<float4> xNormalMap;
float3 xLightPosition;
float4 xLightColor;
uint xWidth;
uint xHeight;

sampler Sampler =
sampler_state
{
	Texture = xNormalMap;
	MipFilter = LINEAR;
	MinFilter = LINEAR;
	MagFilter = LINEAR;
AddressU = CLAMP;
AddressV = CLAMP;
AddressW = CLAMP;
};

float4 main(float4 color : COLOR0, float2 texCoord : TEXCOORD0) : COLOR0
{
	float4 tex = tex2D(TextureSampler, texCoord);

float3 texC3;
texC3.x = texCoord.x * xWidth;
texC3.y = texCoord.y * xHeight;
texC3.z = 0;

float4 shadingResult = float4(0,0,0,0);

float4 normal = xNormalMap.Sample(Sampler, texCoord) - float4(.5,.5,.5,.5);
float specular = xSpecularMap.Sample(Sampler, texCoord).r;
float3 displacement = normalize(xLightPosition.xyz - texC3);

float intensity = dot(normal.xyz, displacement);
//shadingResult += intensity * xLightColor;

float3 halfvector = normalize((displacement + float3(0,0,-1)) / 2);
float specintensity = max(0, dot(normal.xyz, halfvector));
shadingResult = specintensity * xLightColor;

return specintensity; //tex * shadingResult * color;
}

technique Light
{
	pass Pass1
	{
		PixelShader = compile ps_2_0 main();
	}
}

The key area starts around line 40. specular is the R value of a passed-in specular map, which is correct and has stuff in it (this is what I see if I pass it straight through):
Posted Image

And if I pass through only the calculated intensity of the specular light, this is what I see:
Posted Image

But if I return the simple product of these two floats, all I see is black with an extremely faint circle at the location of the light, even if I augment the shading intensity hundredfold.

Thanks in advance for any advice.

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