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reading .wav file


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#1 lomateron   Members   -  Reputation: 342

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Posted 24 June 2012 - 04:05 PM

Here i am reading the sound data chunk part of a wav file:

16bit, 2 channels
The sound is a music with all kinds of frequencies.
[source lang="cpp"]short p1[2]; //array were a sample of sound will be, right and left sound.for(int i=0; i < 1000000 ;i++) { fread(&p1,sizeof(short),2,fp); }[/source]


so after this i am debuging the for loop, checking the value of p1[0] and p1[1]
Logically the value should be between -32768 and 32767 but it just goes between like -67 to 20.
why is that?
I made the soundfile with code and i can play it in windows media, so i know the data should have a -32768 or 32767 somehere but it doesnt.

OOPS posted in game programming it was for general programming.how can i move it.

Edited by lomateron, 24 June 2012 - 04:16 PM.


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#2 mhagain   Crossbones+   -  Reputation: 7979

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Posted 24 June 2012 - 05:17 PM

Array/pointer "equivalence" - should be:
fread(p1,sizeof(short),2,fp);

(Note the missing '&' before p1).

Edited by mhagain, 24 June 2012 - 05:18 PM.

It appears that the gentleman thought C++ was extremely difficult and he was overjoyed that the machine was absorbing it; he understood that good C++ is difficult but the best C++ is well-nigh unintelligible.


#3 zacaj   Members   -  Reputation: 643

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Posted 24 June 2012 - 05:17 PM

I dont think you need the & in front of p1 when p1 is an array.

#4 lomateron   Members   -  Reputation: 342

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Posted 24 June 2012 - 06:06 PM

Still same values, why is that?
i am checking what are the max and min values that p1 gets during all the loop and they are still the same.

Edited by lomateron, 24 June 2012 - 06:37 PM.


#5 BeerNutts   Crossbones+   -  Reputation: 2946

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Posted 24 June 2012 - 08:55 PM

1st, no &, as mentioned above, since p1 is already a pointer (an array, really, but p1 points to a memory location).
2nd, use unsigned short when reading the data out.
3rd, I would also use a hex-editor to open the file, and look at the actual file data and see what it's supposed to look like. And, I would do it in Hex. The values are probably OK.
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#6 lomateron   Members   -  Reputation: 342

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Posted 25 June 2012 - 04:58 PM

I solved it, instead of using

short p1[2];
I used
unsigned short p1[2];

ANd now the values inside p1 goes from 0 to 65534.




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