testConstness(tempCopy); //compiles, but storage of reference/pointer will be invalid as soon as the main() function exits -> imagine this in other //function
Nope, that won't compile. For two reasons. One, you're not calling the function, you're passing the address of the function. And two, even if you did call the function, it would be binding a non-const reference to a temporary, which is illegal.
testConstness(constCopy); //won't compile
No, it won't, but that's because the constCopy function isn't declared right (it's missing parentheses at the end), and also because you're not calling it here (again, you're passing the address of the function). Then, of course, you have the whole "binding a non-const reference to a temporary" issue. But yes, you are right in that you can't use a non-const reference to refer to a const object.
const foo isconst;
testConstness(isconst); //won't compile
These two are actually right.
Edited by Cornstalks, 04 April 2013 - 08:34 AM.
Alright, now that I'm on a computer instead of a phone, I can properly respond to The King2's post...