class x{
public:
int arr[10];
};

How do you create a pointer to arr?

x xObj;
int *p = xObj.arr;

No,i mean with the special syntax for pointer to member,like:

x d

x* z = &d;

int x::*mypointer = &x::arr;

the above would work if arr would be a simple int,not an array

I believe it would be like this.

int (x::*mypointer)[10] = &x::arr;

Yes, pointers can be confusing. But there was only one answer to this question, not three. My first response, for example, was not the kind of pointer he was looking for and thus is not an answer. Member pointers are different from pointers. My second response is the only answer in this case if he wants a member pointer to an array of 10 integers.

Also, if the wrap around syntax of array types is confusing, you can use a typedef to define the pointer type in parts:

typedef int IntArray10[10];
IntArray10 x::*mypointer = &x::arr;

@LordRhys,don't worry,I've seen a lot of code but I never actually enocuntered those pointers.I asked because I had an exercise about them.You can always make a simple pointer and point it at the array.

Even though you won't see many things used in c++,it's good to have an ideea about them,because you might encounter them once.