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Fragments view space from depth in WebGL


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#1 Pris0n   Members   -  Reputation: 111

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Posted 27 June 2013 - 12:02 PM

Hi there,

 

I'm currently trying to implement a SSAO in WebGL. My inspiration is this site: Tutorial

 

But my current problem is to reconstruct the fragments view space position from depth.

If I understood the viewray right it is a vector from the camera to a point on the far plane. I read through all of MJP s articles, but they confused me somehow.

I render a fullscreen quad, so i get the TexCoords and the positions of x and y of the vertex. So my thought was, that only z is needed which I filled with the linearized depth value at the position of the TexCoord.

 

 

For visualisation I switched the coordinates from -1,+1 to 0,1; But even with that info I don't really know what the outcome should look like.

vec3 viewRay = vec3(vViewRay.xy * 0.5 + 0.5 , linearDepth);

Here is a fiddle of my 2 shaders I use.

http://jsfiddle.net/Peters_Stuff/8ddkt/

 

 

Thanks for your ideas

:)



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#2 Pris0n   Members   -  Reputation: 111

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Posted 28 June 2013 - 02:57 AM

I continued my research and found out that I need to project my vertices of the quad to the corners of the farplane by multiplying

 it with the inverse of my perspective matrix in the vertex shader.

So far so good.

vViewRay = vec3(vec4(VertexPosition, 1.0) * invPerspectiveMatrix).xyz;

Displaying viewray in the fragment shader looks like this:

LLzCnbZRIz.jpg

 

 

I think it looks just fine with exception of the missing blue values. This could possible be the result of the z-value of my quad all being 1.0 before the inverseprojection.

So it is gone after that. Putting z of the far clipping plane (z=1000); in, didn't change anything.

 

Any suggestions?


Edited by Pris0n, 28 June 2013 - 02:58 AM.


#3 marcClintDion   Members   -  Reputation: 431

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Posted 29 June 2013 - 12:54 PM

Normals will also look like that if you pass them out through the color output. 

 

Try using the following formula to retool all the 3D vectors into the "color quadrant"??? I think I just made that name up???... or color space if you prefer.  Anyways, by this I mean: all positive numbers, between 0.0 and 1.0. as vectors they are -1.0 to 1.0.  Colors with negative numbers in them have peculiarities that are not entirely intuitive.  For example, what you are seeing there.

 

When a 3D modeling program range compresses normals from 3D space to a color texture it uses this formula ->  

 

(normal+ 1.0) * 0.5;  

                               

For you it would be:

 

 (vViewRay + 1.0) * 0.5;  

 

It squishes all three vectors to half their sizes then pushes everything towards the positive... well... color quadrant.

 

Your vector should now look like a world space normal map now I'm thinking...


Consider it pure joy, my brothers and sisters, whenever you face trials of many kinds, because you know that the testing of your faith produces perseverance. Let perseverance finish its work so that you may be mature and complete, not lacking anything.


#4 Pris0n   Members   -  Reputation: 111

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Posted 01 July 2013 - 07:42 AM

Ah ok, maybe I confuse you :)

 

I want to reconstruct my VertexPosition in view space from depth. So far I read through tons of artictles but wasn't able to get thinks working.

 

vec3 origin = should be my final VertexPosition in view space

 

Currently I'll do this, taken from http://mynameismjp.wordpress.com/2010/09/05/position-from-depth-3/

vec3 origin = vec3(screenPos.xy, 1.0) * linearDepth;

screenPos are the ndc of the screen:

vec2 screenPos = vec2(gl_FragCoord.x / 512, gl_FragCoord.y / 512.0);

But I dunno what origin should look like so i can validate the that it worked.






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