A question about this code in a unity pong tutorial:
// Give the ball some initial movement direction
rigidbody2D.velocity = Vector2.one.normalized * speed;
Why do we have to normalize the Vector2.one vector if its already one?
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Posted 04 September 2014 - 03:25 AM
Due to the documentation, Vector2.one is the vector (1,1) which has the length sqrt(1^2 + 1^2) = 1.4142 approx., so it is not of unit length.
EDIT. For the case you do not know: The normalization ensures that the length of the vector is 1, not that all of its components are 1. So, in this case, the result of normalization would be approximately
(1,1) / length( (1,1) ) = (1,1) / 1.41412 = (0,707,0.707)
This step ensures that the velocity vector has a length equal to the value of speed. Otherwise its length would depend on the actual direction, so you would have higher speed in diagonal directions than in principal directions.
Edited by haegarr, 04 September 2014 - 03:35 AM.