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Is this the formula for distance from a plane?


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#1 WhatEver   Members   -  Reputation: 114

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Posted 02 January 2002 - 10:24 AM

TrinaglePos=Tx*Nx+Ty*Ny+Tz*Nz; PointPos=Px*Nx+Py*Ny+Pz*Nz; Distance=sqrt(PointPos-TrianglePos); T is a Triangle vertex. P is the Point in space. N is the Normal. If I'm right, I'm really starting to understand what the Dot Product does. Edited by - WhatEver on January 2, 2002 5:25:41 PM

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#2 Dredge-Master   Members   -  Reputation: 175

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Posted 05 January 2002 - 05:36 AM

was easier than typing it out


you weren't too far off


for programming purposes, you probably can't guarentee that |ax+by+cz+d| is positve, and you don't want to call "sqrt()" too many times, so




When coding it, do something like

distance=a*x+b*y+c*z+d;
distance=sqrt(distance*distance/(a*a+b*b+c*c));




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Edited by - Dredge-Master on January 5, 2002 12:41:54 PM




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