Hey there, can anyone help me figure out why this won't work?:

  #include <iostream.h>

class myClass
{
public:
	myClass(void)
	{
		think = myFunction;
	}
	void (*think)(void);
	void myFunction (void)
	{
		cout << "Hello" << endl;
	}
};

void main (void)
{
	myClass object;
	object.think();
}  

When compiling in Microsoft Visual C++ 6.0 I get the following error message: c:\cstuff\ptofunction\pointer.cpp(8) : error C2440: '=' : cannot convert from 'void (__thiscall myClass::*)(void)' to 'void (__cdecl *)(void)' There is no context in which this conversion is possible Thanks in advance! ========================= "The staff in the hand of a wizard may be more than a prop for age," -Hamá the doorward from 'Lord of the Rings' by J. R. R. Tolkien Edited by - HimitsuMonban on January 5, 2002 3:05:59 AM

I have found out through a lot of trial-and-error that the following code works:

  #include <iostream.h>class myClass{public:	void myFunction(void)	{		cout << "Hello" << endl;	}};typedef void (myClass::*pmFunction)(void);pmFunction pMyFunction = &myClass::myFunction;void main(){	myClass object;	myClass* pObject = &object	(pObject->*pMyFunction)();}  

But this still does not solve my problem of being able to have the pointer inside the class itself. Cany anyone please help me rewrite this so that I can have a pointer as a member of a class which can point to a member function of that class? Thanks in advance!

=========================
"The staff in the hand of a wizard may be more than a prop for age," -Hamá the doorward from ''''Lord of the Rings'''' by J. R. R. Tolkien