steven166

Thank eppo for reply, the syntax you see is right. The first texture will be bound to the 4th slot, and the second texture at the 5th slot...etc. About Texture2DArray, I have tried to use it, but there is a problem with texture's resolution if there are many textures.

Thank everybody for the reply,

For binding the textures:

pd3dImmediateContext->PSSetSamplers( 0, 1, &g_pSamLinear );

//g_sFileNames stores list of texture names
//g_pTextures is two dimensional array of shader resource view
pd3dImmediateContext->PSSetShaderResources(4, g_sFileNames.size(), g_pTextures);

As I sampling at the current pixel, everything is fine if the current pixel use the first texture in the array, otherwise the color is black . 

For pre-compiling using fxc, I used

fxc simple.hlsl /T vs_5_0 /EVS /Fo "VSCompile.cso"

and 

fxc simple.hlsl /T ps_5_0 /EPS /Fo "PSCompile.cso"

Sorry, I just test it before posting. Actually, it is b1

Thank Zaoshi Kaba, but I even modify the shader for debug, but values of three arrays are the same (1, 0, 0)

cbuffer cbPerFrame: register(b1)
{
float4x4 g_mMatrixArray[10];
}

VS_OUTPUT RenderSceneVS( VS_INPUT input )
{
    VS_OUTPUT Output;    

    float4 temp = 0;
    float3 posL = float3(1.0f, 0.0f, 0.0f);
    float4x4 temp1 = g_mMatrixArray[0] + g_mMatrixArray[1] + g_mMatrixArray[2];
    temp = mul(float4(posL, 1.0f), temp1);

    // Transform the position from object space to homogeneous projection space
    Output.Position = mul( float4(temp.xyz, 1.0f), g_mWorldViewProjection );
    
    Output.Color = input.Color;

    return Output;
}

As you can see the image, all matrices have the same value and they are float1x4 instead of float4x4. I do not understand

Vexal, it is not what I meant. Just imagine that in shader, I have a constant buffer which is an array of matrix gBoneTransform[96]. And in C++ source code, I want to update that matrix array. For example, people use SetMatrixArray(array, count) to update the matrix array in an effect. But I am not sure that is there any way to do same thing without using an effect?