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wtfmates

Member Since 24 Oct 2012
Offline Last Active Nov 27 2012 09:01 AM

In Topic: Yet another pong question, this time about ball physics.

24 October 2012 - 09:58 AM

You could consider your paddle as a rectangle with two half circles at the ends. Then find out what the ball hits and perform collision response accordingly (for the rectangle, reflect the velocity about the surface normal, for the half circles do the same but the normal depends on the location the ball hit - and this'll make the ball bounce off at different angles if it hits the edges of the paddle). Though this kind of design can't really be shoehorned in the typical "if ball position is less than zero do such and such" type of code - you'd need to start from scratch and define actual objects, run correct intersection loops, etc..

I was afraid of that, but I'm still attempting to shoehorn it into the code. I've found a solution that involves taking the location of the center of the ball and figuring out where it collides in relation to the center of the paddle and adjusting it's direction, speed, and position accordingly. If that doesn't work out I'll create three different collision boxes for each paddle. I know I shouldn't be, but I'm very lazy and attempting to shortcut writing completely new code as much as I can.

Thank you for all of your help and suggestions though. When I work something out I'll post it here and hopefully you guys can look it over and let me know where I need improvement.

There are multiple ways you could do this. I think the simplest would be to have it check each 1/3 of the paddle (as you suggest), and, do something like this:

```if (PaddleHit()) {
// This covers the middle part of paddle hit
ballSpeed.Y *= -1;
// increase Y speed, so it goes up at a tighter angle:
ballSpeed.Y *= 2;
}
// decrease Y speed, so it goes up at a wider angle:
ballSpeed.Y /= 2;
}
// Ensure Y-Speed doesn't go above or below a minimum here
}
```
That code above is just a guess. You should really be keeping the velocity as a fraction, so you can perform these computations with greater accuracy.
The other methods of doing this would involve some trigonometry, or some vector math. You're welcome to look up some solutions related to them if you would like.

I just noticed this reply from you. That's a pretty simple way of doing it. I'll give it a go and let you know how it turns out. Thanks for your help

In Topic: Yet another pong question, this time about ball physics.

24 October 2012 - 07:46 AM

You need to push the ball out of the wall/paddle, otherwise the ball's speed will repeatedly get multiplied by -1 and will jitter with zero net displacement. You can do this:

if (ballPosition.Y < 0 || ballPosition.Y > maxY)
{
ballSpeed.Y *= -1;
if (ballPosition.Y < 0) ballPosition = 0;
if (ballPosition.Y > max) ballPosition.Y = max;
}

Or something like that.

Advice taken and I added it to the code. It doesn't seem to have helped the predictability of my ball physics though.

Oh wait, you don't mean it's getting stuck in a corner, or at the top of the screen, you mean it keeps following the same pattern when bouncing around the screen.

Why would the ball bounce different, if it hits the same angles every time, with no other forces on it? I think it's doing what it thinks it should. Now, you can make the ball have different angles coming off the padddle, based on where it hits on the paddle to provide some variation. That's what I'd do.

Yeah, that's what I meant. I'm sorry if I wasn't clear. That sounds like a good idea, but I'm unsure where to start. Will I need to create a separate bounding box for each 1/3rd of the paddle, or is there a simpler way to do it?

Feel free to tell me to stop pestering you guys and go google it if you get annoyed with these questions.

Found this on a website but I'm not clear on exactly what it's doing:

```public void BatHit(int block)
{
if (direction > Math.PI * 1.5f || direction < Math.PI * 0.5f)
{
switch (block)
{
case 1:
break;
case 2:
break;
case 3:
break;
case 4:
break;
case 5:
break;
case 6:
break;
case 7:
break;
case 8:
break;
case 9:
break;
case 10:
break;
}
}
else
{
switch (block)
{
case 1:
break;
case 2:
break;
case 3:
break;
case 4:
break;
case 5:
break;
case 6:
break;
case 7:
break;
case 8:
break;
case 9:
break;
case 10:
break;
}
}
}
```

In Topic: Yet another pong question, this time about ball physics.

24 October 2012 - 07:21 AM

You need to push the ball out of the wall/paddle, otherwise the ball's speed will repeatedly get multiplied by -1 and will jitter with zero net displacement. You can do this:

if (ballPosition.Y < 0 || ballPosition.Y > maxY)
{
ballSpeed.Y *= -1;
if (ballPosition.Y < 0) ballPosition = 0;
if (ballPosition.Y > max) ballPosition.Y = max;
}

Or something like that.

Advice taken and I added it to the code. It doesn't seem to have helped the predictability of my ball physics though.

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