Forgotten to answer to this part:
In HLSL this would mean:
float4x4 transform = mul( mul( rotation, scale ), translate);
float4 worldPosition = mul(vertex, transform);
However in GLSL it would be:
mat4 translation = translate * scale * rotate;
vec4 worldPosition = translation * vertex;
That is not correct in so far that neither HLSL nor GLSL prescribe you to use row or column vectors. It is totally legal to use
HLSL: float4 worldPosition = mul(transform, vertex);
GLSL: vec4 worldPosition = vertex * translation;
BUT: Mathematically neither of the variables in my snippet is the same as its partner in your snippet. Instead, one of them is the transposed form of the other. This is very important, because in HLSL/GLSL you cannot directly see this. Moreover, as long as the matrix in question is a vector, both HLSL and GLSL simply make no distinction between them; instead they simply imply that a pre-multiplicand is a row vector in case that it is a vector at all, and a post-multiplicand is a column vector in case that it is a column vector at all. Nevertheless, in case that the argument is not a vector, you as the programmer has the responsibility to ensure the correct form of the matrix.
For example, you have an own matrix math library that works using column vectors (we let the memory layout aspect aside here). Hence a matrix fetched from the library can be used directly in HLSL when using mul(matrix, vector) as well as in GLSL when using matrix * vector, but it cannot be used in HLSL when using mul(vector, matrix) or in GLSL when using vector * matrix. However, using the transpose operator, it can be used in HLSL as mul(vector, transpose(matrix)) and in GLSL as vector * transpose(matrix).
Hope that helps.