- Sort the complete binary tree (actually an array) so that it becomes a max-heap, thus the first element is always the biggest element.
- Since what we want is exactly the opposite (the last element should be the biggest instead), we swap the first element and the last element.
- Now we have to re-sort the array (except the last element), so that the first element is again the biggest.
- Then we repeat the second step, so that the first element is swapped with the current last element.
- We repeat 2, 3 so that all the elements are sorted.
Below is the pseudo-code of Heap Sort.
Heap Sort(Sorting array A[size])
For each parent node,
if there is any child node, we compare it with bigger child. If the parent
is less, we walk down the parent until none of its new children nodes are
While we do not reach the first cell,
swap the first cell with the last cell.
Change the last cell index to the cell preceding the last cell.
Walk down the first cell until none of its new children nodes are greater.