• entries
    146
  • comments
    436
  • views
    197637

Just for the record

Sign in to follow this  
Washu

134 views

This is my not-really-trying attempt at capn_midnights contest:

#include
#include
#include
int main(){float f[] = {1.9518526e-019f, 1.4918509e-019f};int t[] =
{544024393, 1852401780, 0x676e696b, 0x20666f20, 0x756e2061, 1919246957,
1869768224, 540024941, 0x31206f74, 0x203a3030, 0x25483230};while(!(t[3] & (~0
+ 2))){t[7] = std::rand() % 100;for(int *p = t; p - t != 10; ++p)(~??-(p -
t ??' 7)? ((t + 3 - p) ? std::cout.write
((std::allocator::value_type*)p, 4) :

std::cout.write(std::string::pointer(f),4), std::cout) : (std::cout.rdbuf()->sputn((std::streambuf::char_type*)f + 4, 4), std::cout));while((t[3] >>

(sizeof(int) * 8 - 8)) - t[7])(std::cin>>t[3], t??(3??) ??' ??-0 + 2 ?
std::cout : (std::cout<<char(*((char*)t+5) - 32)<<*((char*)t+22)<<*((char*)t+6)

<<char(0x6C), std::cout<<" "<<char(*((char*)t+5)-0x20)<<*((char*)t+6)<<*

((char*)t+4)<<char(108)<<*((char*)t+16)<<*((char*)t+23)<<'!'<[3??) = t[3] << (24), (((t[3] >> (sizeof(int) * 8 - 8)) ??' (t[7] & 0xff)) ?
((t[3] >> (sizeof(int) * 8 - 8)) - (t??(7] & 0xff) > 0 ? (std::cout.rdbuf()-
>sputn("Too high.", 9), std::cout)<low."<Correct!"<Again?
(Y|N): ", (t[7] |= (std::cin.ignore().get() << 0x10)), std::cout, t[3] |= !
((char(t[7]>>0x10) > 0x61 ? (~char(??-(t??(7]>>0x10))) - 32 : char(t[7??)
>>0x10)) ??' '0' + 0x1E));}}



Sign in to follow this  


1 Comment


Recommended Comments

Create an account or sign in to comment

You need to be a member in order to leave a comment

Create an account

Sign up for a new account in our community. It's easy!

Register a new account

Sign in

Already have an account? Sign in here.

Sign In Now