• # The V-aRms Race Has Begun: VIVE Drops Price $200 GameDev Unboxed ## This is only the beginning, VRm I right? Not unlike an arms race, the VR price war has only begun. Who has the best Equipment? Early this Summer, Oculus had a massive sale on their device, the Oculus Rift, ending in a permanent price drop. HTC is now following suit, cutting out the sale, dropping the price altogether on their Vive Head-Mounted Display. Yesterday, The HTC Vive took a hefty slash in price, dropping from their$799 price tag, down to $599. This comes as no surprise after the Oculus Rift dropped down to$399 earlier this Summer on sale. At the end of the sale, the price raised back up to $499 as the final price,$100 less than previous to the sale.

The HTC Vive comes with plenty of their worth for the price, too. Along with the head-mounted display, accessories include two wireless controllers, two bases stations, comfort-related materials, and everything purchasers need to get going (cords, etc.). Additionally, the system comes with Google Tilt Brush, Everest VR, and Richie’s Plank Experience as promotional content, as well as one-month subscription to Viveport.

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• Hi,
I used the 3D shortest distance between two line segments algorithm at this website: http://geomalgorithms.com/a07-_distance.html#dist3D_Segment_to_Segment
This function in Python is checking if two capsules intersect. I checked the algorithm from the website and it seems to work. I tried implementing an epsilon to help with floating point error, but I don't think I did it correctly. Help would be much appreciated.
def check_intersection(particle1,particle2): decimal.getcontext().prec = 100 epsilon = 2**-52 #implement epsilon small_num = 0.00000001 #number to check if they're closely parallel u = particle1.get_s() #s1 v = particle2.get_s() #s2 p0 = particle1.get_p1_position() #P0 q0 = particle2.get_p1_position() #Q0 w = np.array([p0[0]-q0[0], p0[1]-q0[1], p0[2]-q0[2]]) #distance from 2 particles from their p1's a = u[0]**2 + u[1]**2 + u[2]**2 #dot product of u*u. Always >=0 b = u[0]*v[0] + u[1]*v[1] + u[2]*v[2] #dot product of u*v. c = v[0]**2 + v[1]**2 + v[2]**2 #dot product of v*v. Always >=0 d = u[0]*w[0] + u[1]*w[1] + u[2]*w[2] #dot product of u*w e = v[0]*w[0] + v[1]*w[1] + v[2]*w[2] #dot product of v*w D = (a*c)-b**2 #always >=0 #Set all to defaults sc = sN = sD = D #sc = sN / sD, default sD = D >= 0 tc = tN = tD = D #tc = tN / tD, default tD = D >= 0 if D**2 < small_num: # checks if SCs are parallel sN = 0.0 # force using point P0 on segment S1 sD = 1.0 # to prevent possible division by 0.0 later tN = e tD = c else: # get the closest points on the infinite lines sN = (b * e) - (c * d) tN = (a * e) -(b * d) if sN < 0.0: sN = 0.0 tN = e tD = c elif sN > sD: # sc > 1 => the s=1 edge is visible sN = sD tN = (e + b) tD = c if tN < 0.0: # tc < 0 => the t=0 edge is visible tN = 0.0 # recompute sc for this edge if -d < 0.0: sN = 0.0 elif -d > a: sN = sD else: sN = -d sD = a elif tN > tD: # tc > 1 => the t=1 edge is visible tN = tD # recompute sc for this edge if (-d + b) < 0.0: sN = 0.0 elif (-d + b) > a: sN = sD else: sN = (-d + b) sD = a # division to get sc and tc if abs(sN) < small_num: sc = 0.0 else: sc = sN / sD if abs(tN) < small_num: tc = 0.0 else: tc = tN / tD # difference of 2 closest points dP = np.array( [w[0] + (sc * u[0]) - (tc * v[0]), w[1] + (sc * u[1]) - (tc * v[1]), w[2] + (sc * u[2]) - (tc * v[2])] ) # dP = w + np.multiply(sc,u) - np.multiply(tc,v) #S1(sc) - S2(tc) close_d = (math.sqrt(dP[0] ** 2 + dP[1] ** 2 + dP[2] ** 2) ) # closest distance b/w 2 lines # check if distance <= radius * 2, if so, INTERSECTION! diff = abs( close_d - (2*S_RADIUS) ) if(diff <= epsilon): return True else: return False

• Our team at Darkstar Games is looking for some motivated developers to join our new TCG MMORPG game called "Greater Powers".

We are previewing KS for Q1 2020 and are set to create a unique and epic videogame !
Our team members work for corporate equity (corporate shares).
Every team member who has shown active participation is granted stock option in the corporation. And Department directors will be distributing cash bonuses to team members who contribute significantly to the project during development.

Skillset especially needed:
-> Concept artist
-> Rigger
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-> C# programming
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-> Good knowledges level in Unity3D

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Hope to hear from you soon !

• By Cacks
Hi,
I'd like to get & set the OpenGL View Port Matrix but it doesn't work
I'm using the "GL_VIEWPORT" parameter
any ideas?