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Open file

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i have this piece of code for a commondialog: OPENFILENAME ofn; char szFileName[MAX_PATH] = ""; ZeroMemory(&ofn, sizeof(ofn)); ofn.lStructSize = sizeof(ofn); // SEE NOTE BELOW ofn.hwndOwner = hwnd; ofn.lpstrFilter = "Text Files (*.txt)\0*.txt\0All Files (*.*)\0*.*\0"; ofn.lpstrFile = szFileName; ofn.nMaxFile = MAX_PATH; ofn.Flags = OFN_EXPLORER | OFN_FILEMUSTEXIST | OFN_HIDEREADONLY; ofn.lpstrDefExt = "txt"; if(GetOpenFileName(&ofn)) { // Do something usefull with the filename stored in szFileName } how do i use the szFilename in the fopen function to open the file i select??

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Do you mean:

FILE* fp = fopen(szFilename,"rb"); // open for reading

if(fp == NULL)
// error opening file



You might want to also look into the iostream if using C++.

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