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Executing a file

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Hello! I have a very basic question: How can I execute a file from within my running application? A very simple example would be that if the user presses a button, the file "sample.exe" is being launched... Delphi-specific answer if possible, plz! Yours, Indeterminatus --si tacuisses, philosophus mansisses--

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You can use ShellExecute, WinExec (now obsolete) or CreateProcess. Also, if you get the JCL then there''s a function called WinExec32, I believe.

If you want to use ShellExecute then the format is as follows:


procedure DoIt;
ShellExecute(Form1.Handle, ''open'', ''c:\windows\notepad.exe'',
nil, nil, SW_SHOWNORMAL);

Note that the nil parameters are for the parameters for your app and its working directory, in that order. Also, note that you have to pass it a handle as the first parameter: generally you can pass it a form''s handle or the application''s handle, or you can set it to 0. It opens the app using the default viewer (for files), which will in this case mean it just runs the program.

If you want to use strings remember to cast them to PChars first:

ShellExecute(Form1.Handle, ''open'', PChar(Filename),...);

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