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Drawing overlapping windows with no overdraw in GUI system

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For example, two overlapping windows is given like this :
*---------------*
|               |
|               |
|       *---------------*
|       |               |
|       |               |
|       |               |
|       |               |
*-------|               |
        |               |
        |               |
        *---------------*
To draw them with no overdraw, I wanna split them like this :
*------**-------*
|      ||       |
*------**-------*
*------**-------**------*
|      ||       ||      |
|      ||       ||      |
|      ||       ||      |
|      ||       ||      |
*------**-------**------*
        *-------**------*
        |       ||      |
        *-------**------*
Is there any efficient algorithm for this? Or is there another algorithm that doesn't use splitting? [edited by - Yoonjae on August 12, 2002 1:41:47 AM] [edited by - Yoonjae on August 12, 2002 1:43:05 AM]

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Guest Anonymous Poster
To find the overlapping area (or to find out if there is one), check:

if( min( rect1.top, rect2.top ) > max( rect1.bottom, rect2.bottom )
&&
min( rect1.right, rect2.right ) > max( rect1.left, rect2.left ) )

then there is an overlap.

If you assign the results (just replace all min(..top...) with (top = min(..top...)) inside all ifs) then you have the overlapping reigon. From that you can find all of the smaller rectangles.

Karg

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Finding overlapping region is easy.
But splitting method shown in above picture is another problem.
I wanna know splitting algorithm that works efficiently in regardless of # of windows.

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