// the integer i want to make a string of.
int a_int = 5;
// the charstring.
char *a_char;
// this is how im trying to do it. i have included stdio.h
sprintf(a_char, "%s", a_int);
// this however makes my program terminate, but if i understand the docs right, this is the way to do it! =(
sprintf
Author
Hello!
I am trying to "convert" a integer to a string so i can print it with TextOut();
However, when i compile, i dont get any errors, but the program terminates imediatly. It runs fine however if i comment the sprintf stuff.
This is how im doing it.
Thanks in advance!
hi olle
you must allocate memory for your string
then use
see sprintf (msdn)
dont forget to "free(a_char);"
[edited by - diego_rodriguez on September 10, 2002 11:12:34 AM]
you must allocate memory for your string
a_char = (char *) malloc (16); // reserves 16 bytes which is sufficient then use
sprintf(a_char,"%d",a_int); see sprintf (msdn)
dont forget to "free(a_char);"
[edited by - diego_rodriguez on September 10, 2002 11:12:34 AM]
It seems you don''t allocate any memory for your
temporary string a_char. A pointer without
allocation is useless.
If you don''t need a_char in the rest of your
program, you''d better define a array of char
like this :
temporary string a_char. A pointer without
allocation is useless.
If you don''t need a_char in the rest of your
program, you''d better define a array of char
like this :
int i = 123;
char temp_str[80]; // change 80 with the number of characters you need
sprintf( temps_str, "the INT i want to disPLAY: %i", i);
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