I want to view a "long" in the MessageBox
Here is a simple version of what I am doing :
long xyz = 4;
char* ok;
ok = (char*)xyz;
MessageBox(NULL,ok,"",MB_OK);
When I execute I get the system error saying :
The instruction at 0x77e13e49......ref memory could not be read"
Could someone help?
My best regards
looks like you''re trying to dereference a null pointer...
this right here is your problem:
long xyz = 4;
char* ok;
ok = (char*)xyz;
you cant'' "cast" a long to a character array. you''ll have to
convert it using a manual algorithm (or one that''s already availible).
i know there''s an atoi() and itoa() function, perhaps there is an
ltoa() function as well, i''m too lazy to look it up
anyway, that''s where the problem is at, im sure you can take it
from here.
-eldee
;another space monkey;
[ Forced Evolution Studios ]
this right here is your problem:
long xyz = 4;
char* ok;
ok = (char*)xyz;
you cant'' "cast" a long to a character array. you''ll have to
convert it using a manual algorithm (or one that''s already availible).
i know there''s an atoi() and itoa() function, perhaps there is an
ltoa() function as well, i''m too lazy to look it up
anyway, that''s where the problem is at, im sure you can take it
from here.
-eldee
;another space monkey;
[ Forced Evolution Studios ]
''In C we had to code our own bugs. In C++ we can inherit them.''
Your guess is right, there is
//char *_ltoa( long value, char *string, int radix );
I am experementing with it.
Thanks
//char *_ltoa( long value, char *string, int radix );
I am experementing with it.
Thanks
For concatenating/embedding variable-format data with/in strings in C, please use snprintf. In C++, use std::stringstream.
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