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basic question

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In the MSDN I read the following example:
int func( char );
int func( int );
void main ()
//   +func;       // error, can't resolve which func to use

   +func( 0 );  // OK

The first will generate an error as the comment states, but the second one compiles. Please tell me: what does that + sing mean in front of the function call? [edited by - xropi on October 18, 2002 9:22:35 AM]

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Compiler Error C2244
''identifier'' : unable to resolve function overload

for those who don''t know them off by heart (c;

no, i don''t know why they''ve got pluses in there

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If memory serves (I don''t have a compiler here at the moment to check), it should compile to "0 + func(0)".

The reason "+func(0)" is required instead of just "+func" is because adding zero to a char is just as valid as adding zero to an int, so you need to give the compiler more information about which function you''re referring to. ("+func(0)" refers to the int version. You''d need to cast the zero explicitly to a char to get the other function instead.)

At least, that''s what my memory tells me. It may be wrong; it''s been a while since I did much C++ coding.

Sean Timarco Baggaley

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