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# Complex number question! (not too hard, though)

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What say would (2 + 3i) * (2 + 3i) be? i is the square root of -1 of course. Thanks!!! return Neff; //God bless gamedev!

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quote:
Original post by Neff
What say would (2 + 3i) * (2 + 3i) be?
i is the square root of -1 of course.

Thanks!!!

return Neff; //God bless gamedev!

(2 + 3i) * (2 + 3i)
(2 + 3i)^2
4+9i^2+12i
4-9+12i

-> 12i-5

It should be that I think... (i*i = -1)

Joakim Asplund
http://megajocke.cjb.net

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*cough* homework *cough*

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quote:
Original post by megajocke
12i-5

Not to be overly picky, but that should be written: -5+12i (Looks correct to me)

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quote:
Original post by Thunder_Hawk
Not to be overly picky, but that should be written: -5+12i (Looks correct to me)

Ok... :-)

And Gamedev's forum seems to have some weird bug with quoting a message which contains a quote...

Joakim Asplund
http://megajocke.y2.org

[edited by - megajocke on November 9, 2002 6:21:16 PM]

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yay, that's the right answer! Thanks!!!

return Neff;

[edited by - neff on November 9, 2002 6:23:23 PM]

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Rutin
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frob
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