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[edited by - Razza2003 on March 4, 2003 2:45:37 AM]
Projectile Simulation Formula
Author
Hi, would somebody be able to help me find a math formula so I can work out the path of a travelling bullet/missle, from a tank. Ive been trying but it wasn't accuracte. I need it to be able to be affected by the projectiles weight, gravity, wind, etc.
If anyone can help it would be greatly appreciated.
Thx for anyhelp you can provide .
[edited by - Razza2003 on March 4, 2003 2:45:37 AM]
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[edited by - Razza2003 on March 4, 2003 2:45:37 AM]
well the formulas are independant of weight
heres a simple one for working out the x and y positions of the projectile(doesnt include wind)
if you fire a projectile with some initial velocity at some angle.. then you can calculate the x and y position of it like this
1st you need the x and y components of the initial velocity
vx = velocity*cos(angle)
vy = velocity*sin(angle)
at any time t the x and y positions of it will be
x=(initial x velocity)*time
y=(initial y velocity)*time+0.5*gravity*(time)^2
those formula will give you the position at any given time..
an easy way to add wind would be too add an acceleration term onto the x position
x=vx*time + 0.5*(acceleration due to wind)*time^2
make the acceleration negative or positive depending on the wind direction.. but be careful not to make it too big.. or you will end up with particles flying all over the place! 0_o
If you simple want air resistence.. then u could use a similar equation as for wind.. but you will need to make the acceleration of it velocity dependant(because things that arnt moving dont experience air resistance).. which means you will have to continuosly calculate its velocity.. but the equation would look something like this
x=vx*time + 0.5*(acc of air*(current velocity))*time^2
[edited by - quant on March 4, 2003 12:14:34 PM]
heres a simple one for working out the x and y positions of the projectile(doesnt include wind)
if you fire a projectile with some initial velocity at some angle.. then you can calculate the x and y position of it like this
1st you need the x and y components of the initial velocity
vx = velocity*cos(angle)
vy = velocity*sin(angle)
at any time t the x and y positions of it will be
x=(initial x velocity)*time
y=(initial y velocity)*time+0.5*gravity*(time)^2
those formula will give you the position at any given time..
an easy way to add wind would be too add an acceleration term onto the x position
x=vx*time + 0.5*(acceleration due to wind)*time^2
make the acceleration negative or positive depending on the wind direction.. but be careful not to make it too big.. or you will end up with particles flying all over the place! 0_o
If you simple want air resistence.. then u could use a similar equation as for wind.. but you will need to make the acceleration of it velocity dependant(because things that arnt moving dont experience air resistance).. which means you will have to continuosly calculate its velocity.. but the equation would look something like this
x=vx*time + 0.5*(acc of air*(current velocity))*time^2
[edited by - quant on March 4, 2003 12:14:34 PM]
Weight do depend. A table-tennis ball behaves diffrently compared to a iron ball of the same size.
But, if you''d care about the weight you''d probably be so picky about the physics that you''d never finnish the physics-code for the ball :-)
But, if you''d care about the weight you''d probably be so picky about the physics that you''d never finnish the physics-code for the ball :-)
If the shape of the object is the same, the wind resistance force is the same... If the mass of the object is greater, the gravitational force is larger.
Sum those forces, then divide by the object''s mass, and the more dense object will have a greater downward acceleration.
Sum those forces, then divide by the object''s mass, and the more dense object will have a greater downward acceleration.
assume for one minute that there is no wind resistance or anything.. just gravity
Newtons 2nd law
F=ma
Law of gravity
F=G*M*m/r^2
where M is the mass of the earth.. m is the object falling to the earth
ma=G*M*m/r^2
m''s cancel
a=G*M/r^2
simple physics really.. everything falls at the same speed
Newtons 2nd law
F=ma
Law of gravity
F=G*M*m/r^2
where M is the mass of the earth.. m is the object falling to the earth
ma=G*M*m/r^2
m''s cancel
a=G*M/r^2
simple physics really.. everything falls at the same speed
right, but if you''re going for reality, there is wind resistance in reality so mass matters.
-me
-me
well air resistance is generally mass independant also..
although more massive objects take longer to reach terminal velocity.. and so would fall faster than less massive objects
although more massive objects take longer to reach terminal velocity.. and so would fall faster than less massive objects
quote:Original post by Anonymous Poster
well air resistance is generally mass independant also..
Mass independant? I've learned and read that it's proportionnal to speed (sometimes squared) and there is a friction coefficient, which depends on the shape of the object and the turbulence that it causes in the air.
Cédric
EDIT; Correction: The force caused by air resistance is mass independant, but the acceleration it creates isn't, whereas the gravity force is mass dependendant, but its acceleration isn't.
[edited by - cedricl on March 7, 2003 11:47:02 AM]
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