vector <long> vLong;
vLong.push_back(13);
vLong.push_back(1);
vLong.push_back(9);
vLong.push_back(7);
vLong.remove_at_position(2); // Removes the 1
vLong.remove_by_value(13); // Removes the 13 at the beginning STL Vectors
Author
Alright, I''m not exactly sure this can be done, but here it goes:
Can I remove a node from a vector (std::vector) that is NOT the last node in the list?
ex.
vector<int> v;...//erase the 5th elementv.erase(v.begin()+5);//erase first occurance of 2v.erase(find(v.begin(),v.end(),2)); [edited by - sjelkjd on March 15, 2003 8:03:05 PM]
Note that insertion/deletion at arbitrary points in a vector is an O(n) operation. If you''re going to do it a lot, consider a list, set, or map instead (depending on your exact requirements).
But... but that''s what HITLER would say!!
But... but that''s what HITLER would say!!
Author
I have a question, and I am starting to NOT like MSVC. It says that (even after I have included the proper header files for vectors) the function "find()" was undeclared. Is there a seperate header file that I must include in order for this to work?
==================
My (soon-to-be) Cherished Cookie of Appreciation:
-- MattB - for WinSock advice --
==================
My (soon-to-be) Cherished Cookie of Appreciation:
-- MattB - for WinSock advice --
Author
While I''m getting good help, I just want to check something...
I know a std::string cannot be passed to a function that wants a char* as an parameter. However, can i simply call the_string.data() and get a char* that is a copy of the data in the string? Also, is it null-terminated?
==================
My (soon-to-be) Cherished Cookie of Appreciation:
-- MattB - for WinSock advice --
I know a std::string cannot be passed to a function that wants a char* as an parameter. However, can i simply call the_string.data() and get a char* that is a copy of the data in the string? Also, is it null-terminated?
==================
My (soon-to-be) Cherished Cookie of Appreciation:
-- MattB - for WinSock advice --
quote:Original post by zackriggle
However, can i simply call the_string.data() and get a char* that is a copy of the data in the string? Also, is it null-terminated?
std::string::data() is not.
std::string::c_str() is.
Note that they return a const char* not a char*. Therefore the string cannot be modified. If you want a modifiable C string, use std::string::copy() (not null-terminated either.)
string str = "Foo.";char buf[1024];int last = str.copy( buf, 1024 );buf[last] = 0; Or something similar.
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Author
One last question. MSVC seems to have a problem with showing me a vector object's members.
Example:
std::vector < int > a;
a. //<-- Does not pop up the little box
Example 2:
std::vector:: //<-- DOES pop up the little box
Nothing changes if I say "using namespace std", other than it screws everything up in fstream.h ...
Any ideas as to why this might happen? I don't think it has much to do with the std:: part, because std::string works just fine. YES, I did #include <vector>
[edited by - zackriggle on March 16, 2003 7:46:48 PM]
Example:
std::vector < int > a;
a. //<-- Does not pop up the little box
Example 2:
std::vector:: //<-- DOES pop up the little box
Nothing changes if I say "using namespace std", other than it screws everything up in fstream.h ...
Any ideas as to why this might happen? I don't think it has much to do with the std:: part, because std::string works just fine. YES, I did #include <vector>
[edited by - zackriggle on March 16, 2003 7:46:48 PM]
IntelliSense is fairly braindead in VC6. Google for visualassist, I think, for a (commercial) solution.
How appropriate. You fight like a cow.
How appropriate. You fight like a cow.
Try declaring the vector this way
vector(int) a;
put it in greater than and less than brackets though. for some reason they didnt show up.
[edited by - Brad8383 on March 16, 2003 7:23:30 PM]
vector(int) a;
put it in greater than and less than brackets though. for some reason they didnt show up.
[edited by - Brad8383 on March 16, 2003 7:23:30 PM]
This topic is closed to new replies.
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