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C++ Problem

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Alright, so its been about a year now since i''ve actually programmed in C++ and I pulled out my old school book with all the exercises and theres this one problem that''s just completely annoying me off the deep end. Its a nested loop problem. I need to make a program that outputs. * *** ***** ******* ***** *** * using one function. So after messing around with it so far this is what I have but it doesn''t work.

int display(int x)
{
for(int i=0; i<x; i++)
if(i%2==1)
cout << "*";
cout << endl;

if(x<7 && temp==0)
display(x+2);
if(x>=7)
{
temp=1;
display(x-2);
}
if (x<=0)
return 0;
return 0;
}

Well that was my two and a half hour attempt to make it work. It doesn''t though and my mind''s a little locked so i''m gonna take a break. Hopefully someone can help me.

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Well I figured it out. I guess I was thinking too hard on how to get out of using the nested loops that i wasn''t thinking clearly.

Recursion can be useful though.
The working code.

  void display(){for (int i=1; i<=7; i++)		if(i%2==1)		{		for(int j=0; j<i; j++)			cout << "*";		cout << endl;		}	for(i=i-2;i>0; i--)		if(i%2==1)	{				for(int j=0; j<i; j++)			cout << "*";		cout << endl;	}}

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This is a diamond.

  #include <iostream.h>#include <conio.h>int main(){    int x=5, y=3;        for(int i=-1; i<12; i++)    {       for(int j=-1; j<12; j++)       {         if(j>y && j<x)         {            cout<<"*";          }         else{            cout<<" ";         }       }       cout<<endl;       if(i<5)       {          x += 1;          y -= 1;       }       else{          x -=1;          y +=1;       }    }        getch();    return 0;}

[edited by - Screams of Chaos on May 7, 2003 2:37:14 PM]

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