Can you return an Array ???
Author
Hi
Was just wondering if it''s possible to pass and return the contents of everyting in a array.
usually you return it through itself by passing it by reference. like this:
void func(int* &array)
{
//do stuff to array
}
or this probably will work also
int * func()
{
int * a;
return a;
}
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void func(int* &array)
{
//do stuff to array
}
or this probably will work also
int * func()
{
int * a;
return a;
}
My Homepage
Julio, you don''t need to pass an array by reference. In fact, that''s remarkably pointless. The second one you have will definitely not work, since you''d have to allocate the array using new, and then rely on the calling code to delete the array it gets. That is a very, very bad idea.
Here is how you work with an array:
That's it.
[edited by - micepick on May 26, 2003 1:05:00 PM]
void ModifyArray(int* array, int size){ for (int i=0; i<size; i++) do something to array[i]; // since the array was passed as a pointer, // modifying it in here will affect the array // in the calling code.} That's it.
[edited by - micepick on May 26, 2003 1:05:00 PM]
If you doesn''t concern about speed, you can pass a whole struct containg an array:
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struct Wazza{ int data[100];};void SomeThing( Wazza whole_struct ); ____________________ ____ ___ __ _
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Or, if you don't want to affect the array that's passed in:
Note that this is analogous to functions like memcpy, which are declared thus:
[edited by - micepick on May 26, 2003 1:17:25 PM]
int* ArrayOp(int* out, const int* in, int size){ // assume the array 'out' was already allocated for (int i=0; i<size; i++) out[i] = some_operation(in[i]); // have the function return a pointer to the output as well, // just for convenience return out; } Note that this is analogous to functions like memcpy, which are declared thus:
void* memcpy(void *dest, const void *src, size_t size) [edited by - micepick on May 26, 2003 1:17:25 PM]
quote:Original post by exodus7
Hi
Was just wondering if it''s possible to pass and return the contents of everyting in a array.
Yes, but I cannot think of a reason you would ever want to. Normally you pass/return a pointer, or use references.
quote:
Yes, but I cannot think of a reason you would ever want to. Normally you pass/return a pointer, or use references.
i can. i once saw a function that takes in an error message (directX, to be exact) and returns the an array of what error it is. heres what it looked like:
char* GetErrorMsg(HRESULT hr){ switch(hr) { case DDERR_LOSTDEVICE: return "DDERR_LOSTDEVICE"; ... }} btw i dont even think that error msg exists i was just using it as an example
doh, nuts. Mmmm... donuts
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quote:Original post by brassfish89
i can. i once saw a function that takes in an error message (directX, to be exact) and returns the an array of what error it is. heres what it looked like:
char* GetErrorMsg(HRESULT hr){...
Note the return type: char *. Even though the string (char array) is hard-coded, the function is returning a pointer to it, ie. the address of where it sits in memory at runtime.
[edited by - BriTeg on May 26, 2003 12:47:10 AM]
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