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proper way to de-alloc list<type*> ?

Tyson · 2003-05-29T16:55:34

I was just wondering what the accepted "correct" way was to clear an STL list of pointer types. What way will do it correctly without invalidating any iterator you may be using during the clearing process? eg: list<string*> myList; myList.push_back( new string("test") ); list<string*>::iterator it; for(it=myList.begin(); it != myList.end();it++) { delete *it; } myList.clear(); is that a correct way to do it? Thanks! ============================ A guy, some jolt, and a whole lot of code

General and Gameplay Programming Programming

Started by Tyson May 28, 2003 04:14 PM

10 comments, last by Tyson 20 years, 11 months ago

dalleboy

324

May 29, 2003 02:33 PM

quote:Original post by civguy
I don''t know how it solves memory leaks either. If it was totally transparent, it would solve them. But now that I have to actively type
typedef boost::shared_ptr<string> SharedStringPtr;
And then use SharedStringPtr everywhere, so it''s actually more burden than adding a deleteContainer(cont); into the destructor.

As I said: "you could write your own smart pointer if you want to". This smart pointer could have an implicit constructor (boost::shared_ptr''s constructor is explicit) and an implicit convertion operator to the contained type (boost::shared_ptr doesn''t have an implicit convertion operator, you must go via the get member function), then it will be totally transparent.

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DigitalDelusion

874

May 29, 2003 04:55 PM

for neatness try:

  struct delete_object{  template <typename T>  void operator()(T* p){ delete p;}};for_each( myList.begin(), myList.end(), delete_object());myList.clear();

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proper way to de-alloc list<type*> ?

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proper way to de-alloc list<type*> ?

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