class foobar
{
class foo
{
void bar(){}
};
};
int main()
{
foobar Cfoo;
return 0;
}
reach a function in a sub class?
Author
I need help how would I reach bar()? is it even possible?
You have to have an instance of class foo created somewhere, probably inside foobar...
The way your code was written, you have only defined the classes foobar and foo and created an instance of foobar, but there''s no instance of foo anywhere. Remember, defining a class does not create an instance of it.
class foobar{ public: class foo { void bar() {} } foo foo_;};int main(){ foobar myFoobar; myFoobar.foo_.bar(); return 0;}The way your code was written, you have only defined the classes foobar and foo and created an instance of foobar, but there''s no instance of foo anywhere. Remember, defining a class does not create an instance of it.
You need to declare an instance of the nested class to be able to access it, so you could do
Alternatively, you could make bar static as long as it doesn't access any non-static data in class foo, so this might also work
EDIT: Beaten! Arrgh.
[edited by - AikonIV on June 2, 2003 12:20:46 PM]
class foobar{ class foo { void bar() {} } m_Nested;};int main(){ foobar Cfoo; m_Nested.bar(); return 0;}Alternatively, you could make bar static as long as it doesn't access any non-static data in class foo, so this might also work
class foobar{ class foo { static void bar() {} } m_Nested;};int main(){ foobar::foo::bar(); return 0;}EDIT: Beaten! Arrgh.
[edited by - AikonIV on June 2, 2003 12:20:46 PM]
quote:Original post by Anonymous Poster
Cfoo.foo::bar() maybe?
Only if foo::bar() is defined as static, which it isn''t in this case.
This topic is closed to new replies.
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