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How to pronounce C++

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Read the Bjarne Stroustrup faq posted above. C increment was a little joke that poked fun at it.

Michael Bartman
CEO, Lead Programmer
Dark Omen Studios
http://www.darkomenstudios.com/

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quote:
Original post by Joe-Bob
Actually, I think that C++ MEANS C Increment, but it''s still pronounced Sea Plus Plus.


Its a play on words with the name. C++ is essential the next increment in the C language, and C++ is incrementing the C variable by 1 (given that C is an integer type, which for here we will assume it is).

It kinda goes together, hand in hand, the way I see it.

-----------------------
"When I have a problem on an Nvidia, I assume that it is my fault. With anyone else''s drivers, I assume it is their fault" - John Carmack

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Guest Anonymous Poster
That would be "Sea Post-Incemented"

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quote:
Original post by PhilVaz
Oh no, I remember a 2 billion post thread on this just a couple months ago. I''ll try to find it.

It''s "See Plus Plus" not "See Addition Addition"

That''s nothing. Now figure out how to pronounce

Bjarne Stroustrup

Phil P

[edited by - PhilVaz on July 6, 2003 4:16:41 AM]


What''s the problem with that?? ;-P


However.. I use to call it: ++C :-)

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Since C++ uses the post increment operator... does that mean it''s still C and will be advanced after the current step is complete? Dang, I don''t want to wait for the next release...

quote:

And from what I understand, C# is "sea sharp", not "sea pound" or "sea tic-tac-toe".



Nope. C# is actually pronounced ''c hash''. As in ''cash''. As in Micro$oft

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Guest Anonymous Poster
quote:
Original post by Wildfire
Since C++ uses the post increment operator... does that mean it''s still C and will be advanced after the current step is complete? Dang, I don''t want to wait for the next release...



Urrmm.. actually it means create a temporary with the value of C, increment C then return the temporary. So the advancement is done before the current step is complete.

i.e. "somefunc( C++ );" will advance C before calling the func but the temporary variable will be passed instead of the new value.

Pete

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